Take a break and sharpen yor math skills
I started two watches at the same time. It turned out that
one of them went two minutes per hour too slow,
and the other went one minute per hour too fast. When I looked at them again, the faster one was exactly one hour ahead of the other. How long had the watches been running?
I'm thinking 20 hours but there must be a trick cause that's too easy.
when did you buy them?
Ummmmm yea, I'm with mark,.... 20 hrs. Do I win a FF hat ??? :D
20 hours it is. The WINNERS are eligible to enter the Logerite contest!!!! Additionally, I'll send ya a big ole box of grits!!!!! ;D Ummm Good!!!!
ummmm, 17 hours? :P
I've been figgerin' on this thing for about 2 hours now and still need some more time. My watchs are those 3 minute egg timers and I took some sand out of one and put it in the other and been turnin'em over real regular. If I don't lose count it'll still be awhile. :-/
hmmm
X = number of minutes running
X/60 = 60 - 2X/60
X = 3600 - 2X
3X = 3600
X = 1200 minutes = 20 hrs
;)
YEP! That was easy. Now when are the two watches going to have the same right time again? I bet not before my Wife takes them both back to Wal Mart. :D
ARKANSAWYER
Remember even a broken watch is right twice a day. ::)
Some days the broken watch does better than me :D
I lost count of the egg timers. Had to start over..... I quit :D
:D :D :D :D :D :D :D
Ok here's ya another one.
How many feet in a mile. Hint (5280 feet). Why?????
ummm..... 5280? :D
Because the mille (roman mile) was comprised of 5,000 feet.(real feet)
The English used furlongs (660 feet)
For the English to use miles, they had to change the Mile's length to 8 furlongs (5,280 real feet) so it would match their system of surveying farm land which, was measured in furlongs.
The Statute mile is 8 furlongs, 80 chains, 320 rods, 1760 yards or 5280 feet or, if you are from one of those Metric countries, exactly 1609.344 meters.
Now, if you are talking about Nautical miles?
10 cables = 1 nautical mile = 6080 feet = the angular distance of 1 minute of arc on the earth's surface :P :-/.
http://www.gwydir.demon.co.uk/jo/units/sea.htm
Here's one fer ya's
How many square miles does an aerial photograph, with a scale of 1 inch = 1040 feet, cover ( 1 cm = 12500 cm, metric). Format of the photo is 9 inches by 9 inches.
[Edit]
Solution: 1 inch/1040 feet = X/9 inch
X = 9360 feet
so, 9360feet/5840 feet/mile = 1.60 mile
square that = 2.56 square miles
Note that most aerial photos have 30 % overlap for stereo and if you discount this area on the photo you have 1 square mile toward the centre of the photo without overlap. ;D
[snip]
Here's another one, carefull its loaded :D :D
Assume that two road intersections shown on a photograph can be located on a 1:25,000 scale topographic map. If the measured distance between the intersections is 47.2 mm on a map and 94.3 mm on the photograph, (a) What is the scale of the photograph? (b) At that scale, what is the length of a fence line which measures 42.9 mm on the photograph? AND (c) Is the scale in reference to sea level or terrain elevation? ;)
[Edit]
a) ground distance between the intersection is determined from the map scale as:
0.0472 m x 25,000/1 = 1180 m
1
by direct ratio, the photo scale is:
= 0.0943 m/1180 m = 1/12,513 or 1: 12,500 ( 3 sign. figures)
b) 0.0429 m / 1/12,500 = 536.25 m or 536 m
c) this case its in reference to sea level because measurements were compared with an assumed map datum (height above sea level).
Note: If we took measurements on the ground by measuring the horizontal distance between intersections and compared it to the measured distance on the photo, we would be determining scale in relation to terrain elevation. Don't even need to know the height of the camera lens above sea level in that case. This is called ground truthing the aerial photograph. If you know the height above sea level the camera was when taking the photo then you can determine terrain elevation. Some cameras will record the altitude and stamp it on each photo, taken from the planes instruments. :)
Simple stuff, right? ;)
[snip]
hmm-m I need a metric egg timer :-/
-------ALOT------ :D
ummmm... I GOT IT!!!
20 hours! :)
Tom, great answer!!!!
Swamp, that's a trick question. We gotta know the altitude the pictures were taken from, what kinda camera, the exact geographic location of the map, the method used to develope the film, the property owners full name and birthdate, what type of fence, and if the roads are blacktop, concrete, dirt, or gravel, before we can even begin to calculate an answer!!!! :D
Next question: This one's REALLY easy.
7 months of the year have 31 days; how many have 28?
nah, don't need to know none of that. Its just simple ratio (fractions) math. You didn't pay attention in grade 7. And you thought all that homework with fractions was no good for anything? ;)
:D :D :D :D
All 12 months have at least 28 days in'm and one month has only 28 days 'cept on leap year. ;D
Sneeky guy :D :D :D
Well if you want hard questions then: how far can a dog run into the woods? ;)
Nah, we ain't look'n for nothing complicated like that. :D :D ;D
QuoteWell if you want hard questions then: how far can a dog run into the woods? ;)
About halfway. After that he's running OUT of the woods.
8)
Heck Swamp, I can't hardly even remember being in grade 7, and I'm sure I was interested in a lot more things then perfecting my fractions!!! Really important stuff like cars, girls, ball. You know, really important necessary fun stuff!!!!! Now I can do fractions, and ain't too bad at math. But as I said, my brain still likes to focus more on the more important fun stuff!!! :D :D :D
That's one of them there givens, only some of'm aint none to easy to take. :D :D :D ;D
All of this stuff has been easy so far and all of my dogs just run into the woods half way. Now what I really what to know is "How come I see the same stars every night?"
It will take 20 days for the clocks to have the same time again.
ARKANSAWYER